if ax^3-a^2 x^2-bx-b leaves remainder b when divided by x-a then find the value of a?
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Answer:
-b
Step-by-step explanation:
equate x-a to zero
x-a=0
x=a
p(x)=ax³-a²x²-bx-b
p(a)=a(a)³-a²×a²-b(a)-b
⇒a^4-a^4-ab-b=b
⇒-ab-b=b
⇒b(-a-b)=b
⇒-a-b=b/b
⇒-a-b=1
⇒-a=b
⇒a=-b
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