Question

if ax^3+bx^2+cx+dx is 2.then a is​

Answer 1

Answer:

a=−bx2−cx−dx+2/x3

Step-by-step explanation:

Let's solve for a.

ax3+bx2+cx+dx=2

Step 1: Add -bx^2 to both sides.

ax3+bx2+cx+dx+−bx2=2+−bx2

ax3+cx+dx=−bx2+2

Step 2: Add -cx to both sides.

ax3+cx+dx+−cx=−bx2+2+−cx

ax3+dx=−bx2−cx+2

Step 3: Add -dx to both sides.

ax3+dx+−dx=−bx2−cx+2+−dx

ax3=−bx2−cx−dx+2

Step 4: Divide both sides by x^3.

ax3/x3=−bx2−cx−dx+2/x3

a=−bx2−cx−dx+2/x3

Answer:

a=−bx2−cx−dx+2/x3

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