If ax-3a=12 find the integer value (s) of a for which x is positive no
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Answer:
ax - 3a = 12 -----------(1)
a ( x - 3 ) = 12
x - 3 = 12 / a
x =12+3a / a -----------(2)
putting the value of ( 2 ) in equation (1)
a(12+3a/a)-3a = 12
12a + 3a - 3a = 12
12a = 12
a=12
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