If ax + 4y +3 = 0,bx+5y+3=0 and cx +6y+3=0 are cocurrent lines ,then (a+c)=m find the value of m
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Lets concentrate three equation there is common 3 in each of them if we subtract any two equation the last term will destroyed and remain only two terms.thus again we get three new equations as
(c-b)x+y=0,(c-a)x+2y=0,(b-a)x+y=0
By solving any two of them we will get the answer as a+c=2b
So m = 2b
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