If (ax+b) is a factor of p(x), then it's remainder?, if 3x-1 is a factor of p(x)= x^2-ax then the value of a?
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I don't understand your questionIf (ax+b) is a factor of p(x), then it's remainder?, if 3x-1 is a factor of p(x)= x^2-ax then the value of a?
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1/3
Step-by-step explanation:
If (ax+b) is a factor of p(x), then it's remainder = p(-b/a) = 0
p(1/3)=0
►(1/3)^2 - a(1/3)=0
►(1/3)^2 - a(1/3)=0
► a= 1/3
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