if ax-bx=a2-b2 then find the value of c
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Answer:
Given ax+by=a^2-b^2 ; bx+ay=0
then x+y=?
Adding given equations
ax+by+bx+ay=a^2-b^2
(a+b)x+(a+b)y=a^2-b^2
(a+b)(x+y)=a^2-b^2
(a+b)(x+y)=(a+b)(a-b)
x+y=a-b
Step-by-step explanation:
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