If ax + bx+c and bx2 + ax + c have a common factor x + 1 then show that
c=0 and a=b.
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Answer:
a = b & c = 0
Step-by-step explanation:
If ax2+bx+c and bx2+ax+c have a common factor x+1 then show that c=0 a=b
ax² + bx + c = (x + 1)(dx + e)
=> ax² + bx + c = dx² + (d + e)x + e
=> d = a e = c & b = d + e = a + c
b = a + c
bx² + ax + c = (x + 1)(fx + g)
=> bx² + ax + c = fx² + (f + g)x + g
=> f = b g = c a = f + g = b + c
a = b + c
adding both
b + a = a + b + 2c
=> 2c = 0
=> c = 0
putting this in above
a = b
hence,proved....
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