If ax + by = 1f16; cx + dy = 2510. Find the value of x and y?
Answers
Answered by
1
= 1C9, y = 134
Solution :
Changing it to Decimal,
10x + 11y = 7958 --> 1
12x + 13y = 9488 --> 2
1*12 => 120x + 132y = 95496 --> 3
2*10 => 120x +130y = 94880 --> 4
3 - 4 => 2y = 616 => y = 308
Substituting in 1 => 10x + 3388 = 79=> 10x = 4570 => x = 457
Hence x = 457, y = 308 (in Decimal)
So in Hex => x = 1C9, y = 134.
Solution :
Changing it to Decimal,
10x + 11y = 7958 --> 1
12x + 13y = 9488 --> 2
1*12 => 120x + 132y = 95496 --> 3
2*10 => 120x +130y = 94880 --> 4
3 - 4 => 2y = 616 => y = 308
Substituting in 1 => 10x + 3388 = 79=> 10x = 4570 => x = 457
Hence x = 457, y = 308 (in Decimal)
So in Hex => x = 1C9, y = 134.
Answered by
0
heya..
Answer :
Changing it to Decimal,
10x + 11y = 7958 --> 1
12x + 13y = 9488 --> 2
1*12 => 120x + 132y = 95496 --> 3
2*10 => 120x +130y = 94880 --> 4
3 - 4 => 2y = 616 => y = 308
Substituting in 1 => 10x + 3388 = 7958 => 10x = 4570 => x = 457
Hence x = 457, y = 308 (in Decimal)
So in Hex => x = 1C9, y = 134.
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