if ax+by=a^2-b^2 and bx+ay=0 what is (x+y)?
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Step-by-step explanation:
Given
ax+by=a^2-b^2. .....(1)
bx+ ay=0....…......(2)
Now adding 1 and2
X(a+b)X+(a+b)y=a^2-b^2. (or)
(a+b )(X +y)=a^-b^2
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