Question

if ax +by=a2-b2 and bx +ay =0,what is (x+y)​

Answer 1

a-b

Step-by-step explanation:

Adding both equations we get,

$ax + by + bx + ay = {a}^{2} - {b}^{2} + 0$

Rearranging the terms,

$ax + bx + ay + by = {a}^{2} - {b}^{2} \\ \\ x(a + b) + y(a + b) = {a}^{2} - {b}^{2} \\ \\ (x + y)(a + b) = {a}^{2} - {b}^{2}$

$x + y = \frac{ {a}^{2} - {b}^{2} }{(a + b)} \\ \\ x + y = (a - b)$

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