Question

if √ax-√by=b-a and √bx-√ay=0, find the value of x+y. PLEASE GIVE THE CORRECT ANSWER​

Answer 1

Kindly, refer the above attachment...

__________________

~hope it helps

๑Ꮇαnσgnα

Answer 2

Answer:

given

√ax-√by = b-a ......... (1)

√bx-√ay = 0 ............ (2)

from cross multiplication.,

x y 1

_____________ = ___________ = ________

(-√b) (0) - (-√a) (-b+a) √b(-b+a) - (-√a+0) √ax(-√a)

-√bx(-√b)

x y 1

_________ = _________ = ____________

0 - (b√a-a√a) (-b√b+a√b) +0 -a+b

x y 1

_________ = _________ = __________

-b√a + a√a -b√b + a√b -a + b

x 1

_________ = _____

-b√a + a√a -a + b

x 1

________ = ______

-√a ( -a+b) -a + b

-√a (-a+b)

x = _________

-a+b

x = -√a

same.,

y 1

_______ = ______

-√b(-a+b) -a + b

-√b(-a+b)

y = ________

-a + b

y = -√b

therefore. x= -√a and y= -√b

hope it's help you