Question

If √ax-√by=b-a and √bx -√ay=0,then x+y=?

Answer 1

Answer:

-√a - √b

Step-by-step explanation:

√ax-√by=b-a_________ (1)

√bx -√ay=0__________(2)

(1)-(2)

⇒√ax-√by - (√bx -√ay) = b-a

⇒x√a - y√b - x√b + y√a = b-a

⇒x√a - x√b + y√a - y√b = b-a

⇒x(√a - √b) + y (√a - √b) = b-a

⇒ (√a - √b)*(x + y) = b-a

∴ (x + y) = b-a/(√a - √b) = -(a - b)/(√a - √b)

             = -(√a + √b) (√a - √b)/(√a - √b) [∵ a²-b² = (a+b)(a-b)]

             = -(√a + √b) = -√a - √b