Question

if ax cube + 2 X square + X - 6 has X + 2 is a factor and leaves remainder 4 when divided by X + 4 find the value of a​

Answer 1

Answer:

a doesn't exist

Step-by-step explanation:

f(x) = ax^3 + 2x^2 + x - 6

f(-2) = 0, f(-4) = 4

f(-2) = -8a + 8 - 2 - 6 = 0

-8a=0

a=0

But if we put a=0 to f(-4),

$f(-4)=32-4-6=22\neq 4$

$a\neq 0$

So a doesn't exist.