Question

if (ax ki power 2) ki power 2=a ki power 2 x ki power 6+ x ki power 3+4, then find the value of a
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Answer 1

Step-by-step explanation:

(ax²)² = a²x^6+x³+4

a²x⁴-x³-a²x^6-4 = 0

x³(a²x-1-a²x²) = 4

(a²x²-a²x+1) = -4/x³

a²x(x-1) = -4/x³ -1

a²= [-(4+x³)/x³]/x(x-1)

a² = (4+x³)/x⁴(1-x)

a = √(4+x³)/x²√(1-x)