If ax2 – 7x + c has 14 as the sum of the zeroes and also as product of the zeroes,
find the value of a and C.
anybody please answer correctly fastttttttt.....
Answers
Given :
ax² - 7x + c has 14 as the sum of the zeroes and also as the product of the zeroes.
To Find :
Find the value of a and c
Solution:
As we know that :-
α + β = -b/a
→ 14 = -(-7)/a
→ 14a = 7
→ a = 7/14
→ a = 1/2
And
αβ = c/a
→ 14 = c ÷ 1/2
→ 14 = 2c
→ c = 14/2
→ c = 7
Hence,
The value of a is 1/2 and c is 7
Verification :-
→ ax² - 7x + c
→ x²/2 - 7x + 7
→ x² - 14x + 14/2 = 0
→ x² - 14x + 14 = 0
here,
a = 1
b = -14
c = 14
By using quadratic formula we factorise this
x = -b ± √b² - 4ac/2a
→ -(-14) ± √(-14)² - 4×1×14/2(1)
→ 14 ± √196 - 56/2
→ 14 ± √140/2
→ 14 ± 2√35/2
As we know that :-
sum of zeroes = 14
→ 14 + 2√35/2 + 14 - 2√35/2 = 14
→ 14 + 2√35 + 14 - 2√35/2 = 14
→ 28/2 = 14
→ 14 = 14
LHS = RHS
And
αβ = 14
→ 14 + 2√35/2 × 14 - 2√35/2 = 14
→ 196 - 140/4 = 14
→ 56/4 = 14
→ 14 = 14
LHS = RHS
Hence,
Verified
It shows that our answer is absolutely correct.
ax² – 7x + c has 14 as the sum of the zeroes and also as product of the zeroes.
Find the value of a and c.
14 = -(-7)/a
14a = 7
a = 7/14
a = 1/2
14 = c/(1/2)
14 = 2c
c = 7
ax² - 7x + c
x²/2 - 7x + 7
x² - 14x + 14/2 = 0
x² - 14x + 14 = 0
here,
a = 1
b = -14
c = 14
By using quadratic formula we factorise
x = -b (-,+)√b²-4ac/2a
-(-14)(-,+)√(-14)²-4×1×14/2(1)
14 (-,+)√(196-56/2)
14 (+,-)√140/2
14 (-,+)2√35/2
Sum of zeroes = 14
14 + 2√35/2 + 14 - 2√35/2 = 14
28/2 = 14
14 = 14
L.H.S = R.H.S
14 + 2√35/2 × 14 - 2√35/2 = 14
196 - 140/4 = 14
56/4 = 14
14 = 14
L.H.S = R.H.S