If ax2– 9x + 15 is a quadratic polynomial and
product of its zeroes is –6, then find the value of a
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Answer
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Given : ax² - 9x + 15 is a Quadratic equation , Product of Zeroes = - 6
To find : the value of a
Solution:
ax² - 9x + 15 is a Quadratic equation
Product of Zeroes = - 6
As we know that for a Quadratic equation
ax² + bx + c
the product of Zeroes = c/a
Comparing ax² - 9x + 15 with ax² + bx + c
a = a b = - 19 c = 15
Product of Zeroes = 15/a
product of zeroes = - 6
Equating both
=> 15/a = -6
=> a = -15/6
=> a = - 5/2
Value of a = - 5/2
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