Question

if ax²-9x+15 is a quaratic polynomoal and the product of its zerows is -6, then find the value of a​

Answer 1

Answer:

a=-5/2

Step-by-step explanation:

The product of zeroes is c/a.

So, c/a=15/a.

But, given that, the product of zeroes is -6.

So,

$\frac{15}{a} = - 6 \\ a = \frac{ - 15}{6} = \frac{ - 5}{2}$

Thank you

Answer 2

Answer:

a = -5/2

Note:

★ The possible values of the variable for which the polynomial becomes zero are called its zeros.

★ A quadratic polynomial can have atmost two zeros.

★ To find the zeros of the given polynomial , equate it to zero .

★ If A and B are the zeros of the quadratic polynomial p(x) = ax² + bx + c ; then ;

• Sum of zeros , (A+B) = -b/a

• Product of zeros , (A•B) = c/a

Solution:

Here ,

The given quadratic polynomial is ;

ax² - 9x + 15

Clearly ,

a = a

b = -9

c = 15

Also,

It is given that ,

The product of zeros of the given quadratic polynomial is (-6) .

Thus,

=> Product of zeros = -6

=> c/a = -6

=> 15/a = -6

=> 15/-6 = a

=> a = -15/6

=> a = -5/2

Hence,

The required value of a is (-5/2) .