Question

if ax²+bx+c=0 then prove that
$2c \div \sqrt{b { }^{2} - 4ac }$
plsssssss answer!!!!!!​

Answer 1

Answer:

ANSWER

If b

2

−4ac≥0

Then the roots are real.

Hence

By using quadratic formula, we get the roots as

2a

−b±

b

2

−4ac