Question

If ax²+bx+c and bx²+ax+c have a
common factor X+1 then show that
C=0 and a=b.​

Answer 1

Answer:

us first substitute P(−1)=0 in P(x)=ax

2

+bx+c as shown below:

P(x)=ax

2

+bx+c

⇒P(−1)=a(−1)

2

+(b×−1)+c

⇒0=(a×1)−b+c

⇒a−b+c=0.........(1)

Now, substitute Q(−1)=0 in Q(x)=bx

2

+ax+c as shown below:

Q(x)=bx

2

+ax+c

⇒Q(−1)=b(−1)

2

+(a×−1)+c

⇒0=(b×1)−a+c

⇒−a+b+c=0.........(2)

Now subtracting the equations 1 and 2, we get

(a−(−a))−b−b+c−c=0

⇒a+a−2b=0

⇒2a−2b=0

⇒2a=2b

⇒a=b

Now substitute a=b in equation 1:

a−a+c=0

⇒c=0

Hence a=b and c=0.