If ax²+bx+c and bx²+ax+c have a
common factor X+1 then show that
C=0 and a=b.
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Answer:
Given,
ax^2+bx+c and bx^2+ax+c have common factor x+1
x+1=0
x=-1
substitute x in the above equation
a(-1)^2+b(-1)+c=0
a-b+c=0:eq.1
b(-1)^2+a(-1)+c=0
b-a+c=0:eq2
from equation 1 and 2
a-b+c=0
-a+b+c=0
--------------
2c=0
c=0/2
c=0
substitute c in equation 1
a-b+0=0
a=b
therefore hence showed
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