Question

if ax² + bx + c is exactly divisible by (x-1) (x-2) and leaves remainder 6 when divided by (x+1) , then the values of a, b , c are respectively

Answer 1

Answer:

if ax² + bx + c is exactly divisible by (x-1) (x-2) and leaves remainder 6 when divided by (x+1) , then the values of a, b , c are respectively