Question

If [axbxc]=Band 1 c 1 then !(b*c)X (cxa)​

Answer 1

Answer:

A+1/B=1 equetion (1)

A+1/B=1 equetion (1)B+1/C=1 equetion(2)

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/C

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/C

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)A+1/B=1

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)A+1/B=1put the value of B

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)A+1/B=1put the value of BA+1/C-1/C=1

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)A+1/B=1put the value of BA+1/C-1/C=1A+C/C-1=1

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)A+1/B=1put the value of BA+1/C-1/C=1A+C/C-1=1A=1-C/C-1

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)A+1/B=1put the value of BA+1/C-1/C=1A+C/C-1=1A=1-C/C-1A=C-1-C/C-1

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)A+1/B=1put the value of BA+1/C-1/C=1A+C/C-1=1A=1-C/C-1A=C-1-C/C-1A=-1/C-1

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)A+1/B=1put the value of BA+1/C-1/C=1A+C/C-1=1A=1-C/C-1A=C-1-C/C-1A=-1/C-11/A=C-1/-1

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)A+1/B=1put the value of BA+1/C-1/C=1A+C/C-1=1A=1-C/C-1A=C-1-C/C-1A=-1/C-11/A=C-1/-11/A=1-C

A+1/B=1 equetion (1)B+1/C=1 equetion(2)equetion (1)B+1/C=1B=1–1/CB =C-1/Cequetion (2)A+1/B=1put the value of BA+1/C-1/C=1A+C/C-1=1A=1-C/C-1A=C-1-C/C-1A=-1/C-11/A=C-1/-11/A=1-CC+1/A=1 answer

hope this will help you

Answer 2

Answer:

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