Question

IF AYUSH THROW A BALL AT THE SPEED OF 20 M / S IN THE SKY. THEN WHAT DISTANCE THE BALL COVERED IN 2 SECONDS (HINT : CALCULATE HEIGHT {G=9.8})​

Answer 1

Explanation:

v^2-u^2=2as

=>-400=2×-9.8s

=>20.4=s(approximately)

Answer 2

Explanation:

hogaya itna he ha..........