Question

if b=0,c<0 in ax^2+bx+c=0 then find the value of x​

Answer 1

Answer:

x=1

Step-by-step explanation:

where b=0,where c<0,

where c should be -1,a also 1

a(1)^2+(0)(1)+(-1)=0

Answer 2

Step-by-step explanation:

Given equation is ax² + bc + c =0

Given information, b=0, c<0

So the equation is now ax² — c =0 (as c is -ve. / <0)

So, ax² = c

x²=c/a

x =+√c/a or -√c/a