If B= (-1 2 1 -1) and C = (3/1) . Find Matrix X such that BX=C
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Step-by-step explanation:
It is given that:
X[142536]=[−72−84−96]
The matrix given on the R.H.S. of the equation is a 2×3 matrix and the one given on the L.H.S. of the equation is a 2×3 matrix.
Therefore, X has to be a 2×2 matrix.
Now, let X=[abcd]
Therefore, we have:
[abcd][142536]=[−72−84−96]
⇒[a+4cb+4d2a+5c2b+5d3a+6c3b+6d]=[−72−84−96]
Equating the corresponding elements of the two matrices, we have:
a+4c=−7b+4d=22a+5c=−82b+5d=43a+6c=−93b+6d=6
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