Question

If b =15 degree then the value of 4sin4B.cos4Btan3B is

Answer 1

Answer:

$4 \sin4(b) . \cos4(b) . \tan3(b) \\ = 4 \sin(60) . \cos(60) . \tan(45) \\ = 4 \times \frac{ \sqrt{3} }{2} \times \frac{1}{2} \times 1 \\ = \frac{4 \sqrt{3} }{4} \\ = \frac{ \sqrt{3} }{1} \\ = \sqrt{3}$

hope it helps

Answer 2

Answer:

 The answer will be root 3.

Step-by-step explanation:

This is given that B = 15.

And we have asked for 4sin4B.cos4Btan3B.

Now, put the value of B in the asked question;

Hence,                   ⇒4 * sin 4(15) * cos 4(15) * tan 3(15);

                              ⇒ 4 * sin (60) * cos (60) * tan (45);

                              ⇒ 4 *  $\frac{\sqrt{3} }{2}$  * 1/2 * 1;

                              ⇒ 4 *  $\frac{\sqrt{3} }{4}$ ;

                              ⇒  $\sqrt{3}$

Hence, her is our answer.

That's all.