Question

If b^2-4ac=34 root2+51 what is the nature of the root

Answer 1

Hey

Here is your answer

b^2 - 4ac = 34√2 + 51

since the value is greater than 1 , it has distinct real roots.

Hope it helps you!

Answer 2

$\boxed{ \mathfrak{Heya!!}}$

Given :-

${b}^{2} - 4ac = 34 \sqrt{2} + 51$

Answer :-

The nature of roots is :-

$\bf it \: has \: 2 \: distinct \: real \: roots$

How ??

let's know the Answer

$\bf b^2 - 4ac \: determines \: the \: nature \: of\: roots$

${b}^{2} - 4ac > 0 \: (2 \: distinct \: real \: roots )$

${b}^{2} - ac < 0 \: (no \: real \: roots)$

${b}^{2} - 4ac = 0 \: (2 \: equal \: roots)$

so from the above information we can decide the nature of roots .

$\boxed{ \mathfrak{Hope \: it \: helps \: u}}$