Question

If b = -3, find the value of 3b3 – 2b2 – 6b – 7.​

Answer 1

Here is the answer:

b= (-3)

equation :

$3b^{3} - 2b^{2} - 6b - 7$

put the value of b in equation

=> $3(-3)^{3} - 2(-3)^{2}-6(-3) -7$

=> 3(-27) - 2(9) - 18 - 7

=> -81-18-18-7

=> -124

Hope it helps u

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