Question

If b=c ; a+3b+3c=1 ; -a- 2b-2c=0 , Find a,b,c​

Answer 1

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Answer 2

Explanation:

Since, b=c,

therefore, a+3c+3c=1,

a+6c = 1 ,

-( a +2c +2c)=0,

-(a+4c)=0,

therefore, a+4c =0,

Now, subtracting both equations we get,

a+6c -(a+4c) = 0-1

a+6c -a-4c = -1,

therefore, 2c = -1,

therefore, c = -1/2, b = -1/2

a = -2,

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