Question

if (b+c-a)/a, (c+a-b)/b, (a+b-c)/c are in AP, and a+b+c≠ 0, then:

a. b= ac/a+c
b. b= 2ac/a+c
c. b= (a+c)/2
d. b= √ac​

answer only if sure with the options.

Answer 1

Answer:

The given question is solved in the uploaded photo.

option b is the correct answer.