if b+c-a/a,c+a-b/b,a+b-c/c are in ap then prove that 1/a,1/b,1/c are in ap
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ac-bc = ab-ac/abc1/b -1/a = 1/c-1/bHence they are in AP
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Step-by-step explanation:
c+a-b/b-(b+c-a/a)=a+b-c/c-(c+a-b/
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