Question

if b+c/a=c+a/b=a+b/c and a+b+cnot equal to 0 then show that each of these ratios is equal to 2. Also prove that a²+b²+c²=ab+bc+ca​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

(b+c)/a=(c+a)/b=(a+b)/c

ADDING 1 IN EACH STEP

(b+c)/a+1=(c+a)/b+1=(a+b)/c+1

(b+c+a)/a=(c+a+b)/b=(a+b+c)/c

As a+b+cis not zerop

So 1/a=1/b=1/c

so a=b=c

Thus each ratio

=(a+a)/a=2

Also

a²+b²+c²=3a²

ab+bc+ca

=a*a+a*a+a*a=3a²

So a²+b²+c²=ab+bc+ca