If B C A, then n(AUB) is 1. n(A-B) 2.n(B), 4.n(A)
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1
Step-by-step explanation:
given :
If B C A, then n(AUB) is 1. n(A-B) 2.n(B), 4.n(A)
to find :
If B C A, then n
solution :
b) n( A- B )
hence, the answer is n ( a-b)
Answered by
0
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
Given n(A)=7
n(B)=9
n(A∪B)=14
Substituting in 1
14=7+9−n(A∩B)
⇒n(A∩B)=16−14=2
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