Question

if ( b+c-a)x=( c+a-b)y=(a+b-c)z=2 then find the value of(1/y+1/z)(1/z+1/x)(1/x+1/y)

Answer 1

x= 2/b+c-a

y=2/c+a-b

z=2/a+b-c

put these value in 2nd equation u will the answer u will get answer abc