If Ā= B + C and the magnitudes A, B and
C are 5, 4 and 3 units, the angle between
A and C is-
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letA=5x
B=4x
C=3x
A+B+C=180(BY ASP OF TRAINGLE)
5x+4x+3x=180
12x. =180
x. =180/12
=15
x=15,so
A=5x=5into15= 75
B=4x=4into15=60
C=3x=3into15= 45
Now we want to find the angle between
A and C
ATQ(According to question)
A=B+C
75=B+45
B=75-45
B=30
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