if b+c, c+a, a+b are in HP, then a÷b+c, b÷c+a, c÷a+b =
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1
Answer:
a,b,c are in H.P
⇒
a
1
,
b
1
,
c
1
areinA.P
⇒
a
1
+
c
1
=
b
2
⇒a+c=
b
2ac
⇒ab+bc=2ac
Now,
b−a
b+a
+
b−c
b+c
=
(b−a)(b−c)
(b+a)(b−c)+(b+c)(b−a)
=
b
2
−ab+ac−bc
b
2
+ab−bc−ac+b
2
−ab+bc−ab
=
b
2
−2ac+ac
2b
2
−2ac
=
b
2
−ac
2(b
2
−ac)
=2
Mark it as branliest plzzzz
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