Question

if b cos 0:a then prove that cosec 0+ cot 0 : √b+a/b-a ​

Answer 1

bcosx= a

=> Cosx = a/b = B/H

P = √ (H²-B²)

P= √(b²-a²)

cosecx = H/P = b/√(b²-a²)—(1)

cotx = B/P = a/√(b²-à²)——(2)

Adding (1) and (2)

cosecx + cotx = b+a/√(b²-a²)

cosecx + cotx = √(b+a)²/(b²-a²)

cosecx + cotx = √(b+a)/(b-a) ……Hence proved

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