If b is the mean proportion between a and c prove that a,c,a2+b2,b2+c2 are in proportion
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Step-by-step explanation:
Since, b is the mean proportional between a and c. So b2 = ac.
L.H.S. = a2 – b2 + c2/a-2 – b-2 + c-2
= a2 – b2 + c2/1/a2 – 1/b2 + 1/c2
= (a2 – b2 + c2)/b2c2 – a2c2 + a2b2/a2b2c2
= a2b2c2 (a2 – b2 + c2)/b2c2 – b4 + a2b2
= b4 × b2(a2 – b2 + c2)/b2(c2 – b2 + a2)
b4 = R.H.S.
Hence proved.
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