if b is the mean proportional of a and c prove that the mean proportional of a2+b2 and b2+c2 is ab+ bc
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Solution : -
here it is clearly given that b is the mean proportional between a and c .
therefore, b2 = ac
Now (a 2+b 2)(b 2+c 2) = (a 2+ ac )( ac +c 2) ,
(a 2+b 2)(b 2+c 2) = a(a + c ) c( a + c ) ,
(a 2+b 2)(b 2+c 2) = a c (a + c )2 ,
(a 2+b 2)(b 2+c 2) = b2 (a + c )2
(a 2+b 2)(b 2+c 2) = (ab + bc )2
So,
( ab + bc ) is mean proportional of (a 2+b 2) and (b 2+c 2) . ( Hence proved )
here it is clearly given that b is the mean proportional between a and c .
therefore, b2 = ac
Now (a 2+b 2)(b 2+c 2) = (a 2+ ac )( ac +c 2) ,
(a 2+b 2)(b 2+c 2) = a(a + c ) c( a + c ) ,
(a 2+b 2)(b 2+c 2) = a c (a + c )2 ,
(a 2+b 2)(b 2+c 2) = b2 (a + c )2
(a 2+b 2)(b 2+c 2) = (ab + bc )2
So,
( ab + bc ) is mean proportional of (a 2+b 2) and (b 2+c 2) . ( Hence proved )
AkashMandal:
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Answered by
24
here it is clearly given that b is the mean proportional between a and c .
therefore, b2 = ac
Now (a 2+b 2)(b 2+c 2) = (a 2+ ac )( ac +c 2) ,
(a 2+b 2)(b 2+c 2) = a(a + c ) c( a + c ) ,
(a 2+b 2)(b 2+c 2) = a c (a + c )2 ,
(a 2+b 2)(b 2+c 2) = b2 (a + c )2
(a 2+b 2)(b 2+c 2) = (ab + bc )2
So,
( ab + bc ) is mean proportional of (a 2+b 2) and (b 2+c 2) . ( Hence proved:)
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