If B lies in the second quadrant such
that 3tanB=-4 and A+B=0, then the
value of
15 (11 tan A - sin B - 6 cos A) =
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1
Answer:
Correct option is
B
10
23
3tanA+4=0⇒tanA=−
3
4
=
b
p
⇒p=4x,b=3x⇒h=
p
2
+b
2
=±5x
As A is in II quadrant
sinA=
5
4
and cosA=−
5
3
Therefor
2cotA−5cosA+sinA=−2.
4
3
−5(−
5
3
)+
5
4
=
10
23
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