If b*sin=a*cos, find (a*sin-b*cos)/(a*sin+b*cos)
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Sin²A+cos⁴A
=1-cos²A+(1-sin²A)²
=1-cos²A+1+sin⁴A-2sin²A
=2-2sin²A-cos²A+sin⁴A
=2(1-sin²A)-cos²A+sin⁴A
=2cos²-cos²A+sin⁴A
=cos²A+sin⁴A
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