Question

if b tan B=a,find the value of cosB+sinB÷cosB-sinB

Answer 1

heya,◆◆◆◆

btanB=a
tanB=a/b=p/b. 【where p=perpendicular and b=base of right triangle】

now ,h【height 】=√p^2+b^2. 【by Pythagoras theorm】

h=a^2+b^2


,__________________________________________now from Your question.


cosB=b/h=b/a^2+b^2
.
and sinB=p/h=a/a^2+b^2.

so,putting on your question.then find.

b/a^2+b^2+a/a^2+b^2 ____1 term .

b+a/a^2+b^2
so,(b+a) are cancelled .

then it will be ,1/a+b........1)equation..

and ,again..similarly we find in 2 term.cosB-sinB=1/a-b.......2) equation

now ,dividing both equation 1) and 2 ) according to your question we get.

b-a/b+a Will be answer.

hope it help you.


@rajukumar.◆◆◆◆◆☺

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