Question

If b1, b2, b3 (b1 > 0) are three successive terms of a G.P. with common ratio r, the value of r for
which the inequality b3 > 4b2 - 3b, holds, is given by
(A)r>3
(B) r<l
(C)r=3.5
(D) r = 5.2

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Answer 1

Let us assume that the terms are

a,ar²,ar³ respectively

Now, put the values of each term in the given inequality

b3>4b2-3b1

=> ar²>4ar-3a

Divide by a

r²>4r-3

Solve for the r

You'll get

r<1 and r>3

Answer 2

Answer:

what happened bro

Explanation:

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