Question

If b²-4ac=0 then roots of Qudratic Equation are equal to​

Answer 1

Answer:

Real and NonEqual

Step-by-step explanation:

Roots of equation,

=

$ax { }^{2} + bx + c = 0$

$b {}^{2} - 4ac = 0$

$if \: \: b {}^{2} - 4ac > 0$

$then \: \: \sqrt{b {}^{2} } - 4ac$

will be Real and Nonzero.

Hence,

$ax {}^{2} + bx + c = 0 \: \\ will \: be \: real \: and \: unequal \: to \: b {}^{2} - 4ac > 0$

Answer 2

Answer:

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