Question

If BA x B3 = 57A then the digits A,B are ------- *

5,2

2,5

3,5

5,3

​

Answer 1

Answer:

BA×B3=57A

as B is in 10

′

s place

⇒(10×B+A)×(10B+3)=(57×10)+A

⇒100B

2

+10(A×B)+30B+3A=570+A

⇒100B

2

+10(A×B)+30B+2A=570

⇒2A=570−100B

2

−10(A×B)−30B

⇒10/2A as 10 divides RHS

⇒A=5

or A=0

for A=0, 100B

2

+30B=570

⇒10B

2

+3B=50+7

no B satisfies this as

3B=7

for A=5,100B

2

+80B+10=570

⇒10B

2

+8B=56

⇒5B

2

+4B=28=20+8

⇒B=2

∴B=2,A=5

Step-by-step explanation:

Hope this helps you