Question

If BaCl2, ionizes to an extent of 80% in aqueous
solution, the value of Van't Hoff factor is
1) 2.6 2 0.4 3) 0.8 4) 2.4​

Answer 1

Answer:

1) Van’t Hoff factor describes how colligative properties vary from the actual value.  

2) Here some compounds get dissociate and some get associate due to which no. Of mole of that compound changes and essentially colligative properties depend upon no. Of moles so that vary too.

Here i=calculated colligative properties

$BaCl_{2} ---->Ba(2+)+2Cl(1-)$

$BaCl_{2}$ is 3 as it dissociates to 3 ions

α=0.8

n=2

i=1+0.8(3-1)

i=2.6

so option 1 is correct