If ball is acted upon by the following velocity (1) 3 meter per second East (2) 11 metre per second South (3) 5 under root 2 metre per second North /East. Find the magnitude and the direction of the resulted velocity
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Answer:
<br> due East,
due South an
vec (OS) =5 sqrt 2 ms^(-1)
45^(0)
vec (OS)
5 sqrt 2 cos 45 ^(0) =5 ms^(-1)
5 sqrt 2 sin 45^(0) =5 ms^(-1)
A= 3+ 5 =8 m//s
vec (OP)'
B=11 -5 =6 m//s
vec (OQ')
vec (R)
vec (OT)
/_P'OQ' =90^(0)
vec (R)
<br>
<br> Let
make and angle
with East, then
tan
<br> or
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