Question

If ball is thrown up in the sky, what will happen to its value of ‘g’

Answer 1

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THE VALUE OF 'g' WILL BECOME NEGATIVE.

THAT MEANS IT WILL BE -9.8 or -10 m/s×s.

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Answer 2

g=((G*M*m)/(r^2)).

Thus, where r is the distance from the earth centre as referenced. So, with all other parameters remaining same, the value of r gets squared, hence the value of 'g' should decrease. But as the change in r as compared to the distance of r from the centre to surface is very negligent, hence the change in 'g' will be very less.