if ball is thrown vertically upwards with a velocity of 40 metre per second then what will be the magnitude of displacement after 6 seconds if g is equal to 10 meter per second square??
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s= ut - 1/2gt^2
u, t and gare given
u, t and gare given
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v=40
u=0
t=6sec
g=it is always 9.8m/second square
v=u+gt(equation of motion when object is moving in vertically upward direction)
40=0+-9.8(6)
40-58.8=-18.8
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