Question

if ball thrown in some angle of projection what will be acceleration of ball in horizontal direction​

Answer 1

Answer:

Most people know that a ball without air resistance (traditional projectile motion) goes the farthest if you throw it at a 45 degree angle.

Answer 2

Answer:

As at one point the ball touches the bird it simply means that Horizontal velocity of the ball which is constant over time is EQUAL with that of the bird and as the ball

JUST TOUCHES one time it simply menas that it will be at its top point during that moment so that

it never become at that height again

So if vcosθ is the horizontal velocity of the ball then u=vcosθ and h=

2g

(vSinθ)

2

or vsinθ=

2

2gh

Where v is projection velocity and θ is projection angle.

Now the question ask the horizontal range R=

g

2vsinθ

×vcosθ=

g

2×

2

2gh

×u=2u

2

g

2h